let


Put t=sinx


dt=cosxdx




Putting


A(1+t)(5-4t)+B(1-t)(5-4t)+C(1+t)(1-t)=1


Now Putting 1+t=0


t=-1


A(0)+B(2)(9)+C(0)=1



Now Putting 1-t=0


t=1


A(2) +B(0)+C(0)=1



Now Putting 5-4t=0





From equation(1),we get,






1